6x^2(x+3)+5x(x+3)+(1x+3)=0

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Solution for 6x^2(x+3)+5x(x+3)+(1x+3)=0 equation: 


Simplifying
6x2(x + 3) + 5x(x + 3) + (1x + 3) = 0

Reorder the terms:
6x2(3 + x) + 5x(x + 3) + (1x + 3) = 0
(3 * 6x2 + x * 6x2) + 5x(x + 3) + (1x + 3) = 0
(18x2 + 6x3) + 5x(x + 3) + (1x + 3) = 0

Reorder the terms:
18x2 + 6x3 + 5x(3 + x) + (1x + 3) = 0
18x2 + 6x3 + (3 * 5x + x * 5x) + (1x + 3) = 0
18x2 + 6x3 + (15x + 5x2) + (1x + 3) = 0

Reorder the terms:
18x2 + 6x3 + 15x + 5x2 + (3 + 1x) = 0

Remove parenthesis around (3 + 1x)
18x2 + 6x3 + 15x + 5x2 + 3 + 1x = 0

Reorder the terms:
3 + 15x + 1x + 18x2 + 5x2 + 6x3 = 0

Combine like terms: 15x + 1x = 16x
3 + 16x + 18x2 + 5x2 + 6x3 = 0

Combine like terms: 18x2 + 5x2 = 23x2
3 + 16x + 23x2 + 6x3 = 0

Solving
3 + 16x + 23x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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